Sunday, February 12, 2012

Hard math problem i need help with someone please help?

kelly and julie sond 25 boxes of christmas cookies. to kinds of cookies were being dold. bell cookies sold for $3.oo a box. and candy cane cookes sold for $4.00 a box. they forgot to keep track of how many boxes of each kind they sold, but they now have $88.00. based on this info, how many boxes of each kind of kookie were sold?

Hard math problem i need help with someone please help?
its hard to understand learn how to spell first
Reply:well...

i guess the really mathematical answer would be this:

make 2 equations:

3x+4y=88 (the cost of each box times x or y amount of boxes)

and

x+y=25

then, solve for x on either equation, (the second one is easier)

x=25-y

then plug in into the first equation:

3(25-y)+4y=88

solve and you get y=13 ( thats 13 boxes of the second cookie.)

Plug 13 back into either equation

you will get x=12 (thats 12 boxes of the first cookie.



so your answer would be:

12 boxes of bell cookies and 13 boxes of candy can cookies.
Reply:88-60=28

28/4=7

60/3=20



27-



4x9=36

25-9=16x3=48

48 + 36 = 84



12 x 4 = 48



25-12 = 13



13 x 3 = 39



39 + 48 = 87



13 X 4 = 42



12 x 3 = 36



42 + 36 = 78



i can't get it sorry i tried
Reply:ok, we know that bell cookies are $3 ea., and candycane cookies are $4 each.

so you need 2 equations

b + c =25 total sold

3b+4c=88 amount per box, total made



you can use substitution by solving for b and then plugging it in

b=25-c

so

3(25-c)+4c=88

distribute

75-3c+4c=88

combine like terms

75+c=88

isolate the variable

c=88-75

c=13

plug this value back into your substitution equation

b+13=25

b=12

you cab check by inserting these values into the other equation

good luck

Darlene
Reply:what grade are you in and just divide
Reply:candy canes is for 4 dollars rite so they sold 8 wich = to 32+32=64

and bell cookies for 3 dollars rite so they sold 8 wich =to 24+64=$88





theres 4 groups of 4[cane cones] $4.00

4

4 =8

4

4 =8 8+8=32

4

4 =8

4

4 =8 8+8=32

32+32=64



then theres 4 groups of 3 [bell cookies] $3.00

3

3=6

3

3=6 6+6=12

3

3=6

3

3=6 6+6=12

12+12=24

then its 64+24=88
Reply:12 bell cookies and 13 candy cane cookies that is from my head that is easy though
Reply:X (x) y=25



3x+4y=88



Y=25-x

3x+4(25-x)=88

3X +100-4x=88

3X-4x=-12

-x=-12

x=12

y=25-12





y=13; x=12



Haven't done this in years, curious if I am anywhere close lol
Reply:sorry i have no idea. i suck at math. i would help if i could
Reply:hard english problem needs answered.
Reply:There are several ways to approach these types of problems. I think the easiest for beginners is to try to use one variable for both unknowns... you do it like this...



Let x be the number of boxesof candy cane cookies and (25-x) be the number of box of bell shaped cookies. It doesn't matter which one you pick for x just be consistant.



Now we know the total amount so we can solve this problem.



(3.00) (25 -x) + (4.00) (x) = 88.00



Multiply it out ...



75.00 - 3.00x + 4.00 x =88.00



Now put like terms together



75.00 +x = 88.00



Now subtract 75.00 from each side and you get...



x =13



So that is the number of candy cane cookies.



Now for the other kind of cookie you take 25-13 and get 12 boxes of bell shaped cookies.
Reply:For starters, you need two equations, one for each variable.

Make bell cookies x and candy cane cookies y, then make the coeffieints their values for equation 1.

For equation 2, you know that the number of bell cookies (x) plus the number of candy cane cookies (y) sold will be equal to 25.

Equation One:

3x+4y=88

Equation Two:

x+y=25



Just use elimination. If you still need help, I've included some of thework below.



3x+4y=88 Multiply equation 2 by -3. Then add the

(-3)x+(-3)y=(-3)25 equations together. This cancels the x's.



y=8 This is what you end up with. From

here, just plug your y value into one of

the equations to solve for x.
Reply:let b=bell cookies

and c=candy cane

3b+4c=88....equation Number 1

we know also that

b+c=25....equation number 2

b=25-c

put this the value of b in equation number 1

3(25-c) + 4c= 88

75 - 3c + 4c = 88

75 + c = 88

c = 88 - 75

c = 13

put this value into equation number 2

b + 13 = 25

b = 25 - 13

b = 12

therefor

Kelly and Julie have bell cookies boxes = 13 box

and candy cane boxes = 12 box
Reply:x=bell cookies y=cane cookies

3x+4y=88

x+y=25------%26gt;x=25-y

substitute and we get:

3(25-y) + 4y=88

From this you will get value of y then you can find the value of x
Reply:b=# bell, c=#cane

#1: 3b+4c=88

#2: b+c=25 ... multiply by 3 and subtract from #1:

3b+3c=75

#3: 0b + 1c = 13

so c=13, b=12


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